The Cl- and Cs+ ions in a unit cell of CsCl structure touch along the body diagonals of the unit cell.
The length of the body diagonal is equal to two radii of the Cs+ ion plus two radii of the Cl- ion.
From the radius of one ion and the length of the body diagonal, we can find the radius of the other ion.
Body
Diagonals
in the CsCl Unit Cell
in the CsCl Unit Cell
Body
Diagonal
Outline of three atoms along the body diagonal
rCs+
is the
radius of
the Cs+ ion
radius of
the Cs+ ion
The length of the diagonal is 2 rCl- + 2 rCs+,
or, d = 2 [rCl- + rCs+]
rCl-
+ rCs+
+ rCs+
+ rCl-
rCl- is the
radius of
the Cl- ion
Body
Diagonal
Copyright ©
2003
by: Journal of Chemical Education Software
by: Journal of Chemical Education Software